6v^2=12+6v

Solution for 6v^2=12+6v equation:

6v^2=12+6v

We move all terms to the left:

6v^2-(12+6v)=0

We add all the numbers together, and all the variables

6v^2-(6v+12)=0

We get rid of parentheses

6v^2-6v-12=0

a = 6; b = -6; c = -12;
Δ = b2-4ac
Δ = -62-4·6·(-12)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*6}=\frac{-12}{12}
=-1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*6}=\frac{24}{12}
=2
$